Question #N1009
The function $f(x)$ is defined by $f(x) = \sqrt{x} + 4$. What value of $x$ satisfies the equation $f(x) = 12$?
A. 4
B. 16
C. 64
D. 144
Correct Answer is: C
To solve for x, we first subtract 4 from both sides of the equation to get $\sqrt{x} = 8$. Then, we square both sides of the equation to get $(\sqrt{x})^2 = 8^2$, or $x = 64$. Therefore, the value of $x$ is 64.