Question #N1021
If $x^2 - 6x + 9 = 0$, what is the value of $x$?
A. 3
B. 2
C. 1
D. 0
Correct Answer is: A
The expression $x^2 - 6x + 9$ is a perfect square trinomial: $(x-3)^2 = 0$. Taking the square root of both sides gives $x-3 = 0$, or $x = 3$.