OpenSAT

The radius of the circle is the distance between the center of the circle and any point on the circle. We can use the distance formula to find this distance: \begin{align*} \sqrt{(7-3)^2 + (6-2)^2} &= \sqrt{4^2 + 4^2} \\ &= \sqrt{16 + 16} \\ &= \sqrt{32} \\ &= 4\sqrt{2} \\ &= 4(\sqrt{2 * 2}) \\ &= 4(\sqrt{2})(\sqrt{2}) \\ &= 4(2) \\ &= 8. \end{align*} The radius of the circle is 8, so the correct answer is B.