Question #N112
The function \(f\) is defined by \(f(x) = \sqrt{x^2 + 1}\). What is the value of \(f(\sqrt{3})\) ?
A. 1
B. 2
C. 3
D. 4
Correct Answer is: B
Substituting \(\sqrt{3}\) for \(x\) into the function gives us \(f(\sqrt{3}) = \sqrt{(\sqrt{3})^2 + 1}\) which simplifies to \(f(\sqrt{3}) = \sqrt{3 + 1}\). Therefore, \(f(\sqrt{3}) = \sqrt{4}\) = 2.