Question #N128
If $x^2 + 6x + 9 = 0$, what is the value of $x$?
A. -3
B. 0
C. 3
D. 6
Correct Answer is: A
The expression on the left-hand side of the equation is a perfect square trinomial: $(x + 3)^2 = 0$. Taking the square root of both sides, we get $x + 3 = 0$. Subtracting 3 from both sides, we get $x = -3$.