OpenSAT

To solve for $x + y$, we can use elimination. Multiplying the second equation by 3, we get $3x - 3y = 6$. Adding this equation to the first equation, we get $5x = 16$. Dividing both sides by 5, we find $x = \frac{16}{5}$. Substituting this value of $x$ into the second equation, we get $\frac{16}{5} - y = 2$. Subtracting $\frac{16}{5}$ from both sides, we get $-y = 2 - \frac{16}{5}$, or $-y = -\frac{6}{5}$. Multiplying both sides by -1, we get $y = \frac{6}{5}$. Therefore, $x + y = \frac{16}{5} + \frac{6}{5} = \frac{22}{5}$, or 4.4. Since the answer must be an integer, the closest answer is 6.