OpenSAT

The sum of the solutions to the quadratic equation $ax^2 + bx + c = 0$ is given by $-b/a$. Factoring the given quadratic equation, we get $(x-3)(x-1)=0$. Thus, the solutions to the equation are $x=3$ and $x=1$. The sum of these solutions is $3+1=4$. Therefore, the sum of the solutions to the equation is 4.