Question #N187
What is the value of $\frac{\sqrt[3]{27}}{\sqrt{16}}$?
A. $\frac{3}{4}$
B. $\frac{9}{4}$
C. $\frac{3}{2}$
D. $\frac{9}{2}$
Correct Answer is: A
The cube root of 27 is 3, and the square root of 16 is 4. Therefore, $\frac{\sqrt[3]{27}}{\sqrt{16}} = \frac{3}{4}$.