Question #N27
The function $f(x) = \frac{1}{x-2}$ is defined for all real numbers $x$ except $x = 2$. What is the value of $f(f(3))$?
A. -1
B. 0
C. 1
D. 2
Correct Answer is: C
First, we find $f(3)$: $f(3) = \frac{1}{3-2} = 1$. Then, we find $f(f(3))$, which is the same as $f(1)$: $f(1) = \frac{1}{1-2} = -1$. Therefore, $f(f(3)) = -1$.