Question #N280
The function \(f\) is defined by \(f(x) = x^2 - 3x + 2\). What is the value of \(f(\frac{1}{2})\) ?
A. -\frac{1}{4}
B. -\frac{1}{2}
C. 0
D. \frac{1}{4}
Correct Answer is: D
Substituting \(x = \frac{1}{2}\) into the function, we get: \(f(\frac{1}{2}) = (\frac{1}{2})^2 - 3(\frac{1}{2}) + 2 = \frac{1}{4} - \frac{3}{2} + 2 = \frac{1}{4}\).