Question #N288
If $x^2 + 6x + 9 = 0$, what is the value of $x$?
A. -3
B. 0
C. 3
D. 6
Correct Answer is: A
The equation $x^2 + 6x + 9 = 0$ is a perfect square trinomial, which can be factored as $(x + 3)^2 = 0$. Taking the square root of both sides gives $x + 3 = 0$. Subtracting 3 from both sides, we get $x = -3$.