OpenSAT

To solve for \(x + y\), we can add the two equations together. Adding the left-hand sides, we get \((2x + 3y) + (x - 2y) = 3x + y\). Adding the right-hand sides, we get \(12 + (-1) = 11\). Therefore, \(3x + y = 11\). Since the problem asks for the value of \(x + y\), we can divide both sides of this equation by 3 to get \(x + y = \frac{11}{3}\), or 3.67.