OpenSAT

To find the equation of the line, we first need to find the slope. The slope is given by: \begin{align*} \text{slope} &= \frac{\text{change in }y}{\text{change in }x} \\ &= \frac{-1 - 5}{1 - (-2)}\\ &= \frac{-6}{3} \\ &= -2 \end{align*} Now, we can use the point-slope form of a linear equation, which is: $y - y_1 = m(x - x_1)$, where $m$ is the slope and $(x_1, y_1)$ is a point on the line. We can use either point given in the problem. Let's use (-2, 5): $y - 5 = -2(x - (-2))$. Simplifying this equation, we get: $y - 5 = -2x - 4$ $y = -2x + 1$ Therefore, the equation of the line that passes through the points (-2, 5) and (1, -1) is $y = -2x + 1$.