Question #N398
If $x^2 + 2x + 1 = 0$, what is the value of $x$?
A. -1
B. 0
C. 1
D. 2
Correct Answer is: A
The expression on the left side of the equation is a perfect square trinomial: $(x + 1)^2$. Taking the square root of both sides, we get $x + 1 = 0$. Subtracting 1 from both sides gives us $x = -1$.