Question #N406
In the xy-plane, a circle has a radius of 5 and a center at (3, -2). What is the equation of this circle?
A. (x - 3)^2 + (y + 2)^2 = 25
B. (x + 3)^2 + (y - 2)^2 = 5
C. (x + 3)^2 + (y - 2)^2 = 25
D. (x - 3)^2 + (y + 2)^2 = 5
Correct Answer is: A
The standard form of the equation of a circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2. Substituting the given values of (h, k) = (3, -2) and r = 5, we get the equation (x - 3)^2 + (y + 2)^2 = 25.