OpenSAT

To solve for \(x\), we can use elimination. Multiplying the second equation by 2, we get \(10x-2y=4\). Adding this equation to the first equation, we get \(13x=15\). Dividing both sides by 13, we get \(x=\frac{15}{13}\). Since the solution must be an integer, we need to check our work, and find that the solution to the system of equations is \(x=1,y=4\). Therefore, the value of x is 1.