Question #N507
If $x^2 - 2x - 8 = 0$, what is the value of $x$?
A. -2 and -4
B. 2 and 4
C. -2 and 4
D. 2 and -4
Correct Answer is: C
To solve for the value of x, we can factor the expression: $x^2 - 2x - 8 = (x-4)(x+2) = 0$. Setting each of these factors equal to zero, we get $x-4 = 0$ or $x+2 = 0$, which gives us the solutions $x=4$ or $x=-2$.