Question #N509
The equation $2x^2 + 3x - 5 = 0$ can be factored as $(2x + 5)(x - 1) = 0$. What are the solutions to this equation?
A. -5/2 and 1
B. -5/2 and -1
C. 5/2 and 1
D. 5/2 and -1
Correct Answer is: A
The equation $(2x + 5)(x - 1) = 0$ is true only if one or both of the factors is equal to zero. Setting $2x + 5 = 0$ and solving for x yields $x = -5/2$. Setting $x - 1 = 0$ and solving for x yields $x = 1$. Therefore, the solutions to the equation are -5/2 and 1.