Question #N516
The length of a rectangle is 5 more than twice its width. If the width of the rectangle is $w$, what is the perimeter of the rectangle, in terms of $w$?
A. 10w + 10
B. 6w + 10
C. 8w + 5
D. 7w + 10
Correct Answer is: A
The length of the rectangle is $2w + 5$, so the perimeter is $2(2w+5) + 2w = 4w + 10 + 2w = 6w + 10$.