Question #N533
If \(x+2\) is a factor of the polynomial \(x^3+5x^2-4x-20\), what is the value of \(x^3+5x^2-4x-20\) when \(x=-2\)?
A. -24
B. 0
C. 12
D. 24
Correct Answer is: B
If \(x+2\) is a factor of the polynomial \(x^3+5x^2-4x-20\), then by the Factor Theorem, the polynomial must equal 0 when \(x=-2\). Therefore, \((-2)^3+5(-2)^2-4(-2)-20 = -8 + 20 + 8 - 20 = 0\).