Question #N575
The function $f(x)$ is defined by $f(x) = x^2 - 3x + 2$. What are the x-intercepts of the graph of $y = f(x)$ in the xy-plane?
A. x = 1 and x = 2
B. x = -1 and x = -2
C. x = -1 and x = 2
D. x = 1 and x = -2
Correct Answer is: A
The x-intercepts of the graph of a function occur where y = 0. So, we need to solve the equation $x^2 - 3x + 2 = 0$. This equation can be factored as $(x - 1)(x - 2) = 0$. Therefore, the x-intercepts are at x = 1 and x = 2.