Question #N629
If the function $f(x)=x^2 + 3x - 1$ is defined for all real numbers, what is the value of $f(-2)$?
A. -7
B. -3
C. 1
D. 9
Correct Answer is: A
To find the value of f(-2), we substitute -2 for $x$ in the function: $f(-2) = (-2)^2 + 3(-2) - 1 = 4 - 6 - 1 = -3$. Therefore, the value of f(-2) is -3.