Question #N652
The function *f* is defined by *f*(x) = 3x^2 + 2. For what value of *x* does *f*(x) = 29?
A. -3
B. -1
C. 1
D. 3
Correct Answer is: D
To find the value of *x* that makes *f*(x) = 29, we set the equation 3x^2 + 2 = 29 and solve for *x*. Subtracting 2 from both sides, we get 3x^2 = 27. Dividing both sides by 3, we get x^2 = 9. Taking the square root of both sides, we get x = 3 or x = -3. Since the problem asks for the value of *x* that makes *f*(x) = 29, the answer is x = 3.