OpenSAT

Triangle ABC is a right triangle, so we can use the Pythagorean Theorem: $a^2 + b^2 = c^2$, where a and b are the lengths of the legs and c is the length of the hypotenuse. In this case, AC = 6 and BC = 8, so $6^2 + 8^2 = c^2$. Simplifying, we get $36 + 64 = c^2$, or $100 = c^2$. Taking the square root of both sides, we get $c = \sqrt{100}$, or $c = 10$. Therefore, the length of side AB is 10.