OpenSAT

First, factor the numerator: $\frac{x^2 + 6x + 9}{x+3} = \frac{(x+3)(x+3)}{x+3}$. Then, simplify by canceling out the common factor of $x+3$: $\frac{(x+3)(x+3)}{x+3} = x+3$. Finally, substitute $x = 2$ into the expression: $2 + 3 = 5$.