Question #N713
The graph of the equation $y = \frac{1}{2}(x-3)^2 + 1$ is a parabola. What is the vertex of this parabola?
A. (1, 3)
B. (3, 1)
C. (-3, 1)
D. (1, -3)
Correct Answer is: B
The vertex form of a parabola is $y = a(x - h)^2 + k$, where $(h, k)$ is the vertex. In the given equation, $h = 3$ and $k = 1$. Therefore, the vertex of the parabola is $(3, 1)$.