Question #N744
If $x^2 - 6x + 9 = 0$, what is the value of $x$?
A. -3
B. 3
C. 0
D. -9
Correct Answer is: B
The given equation is a perfect square trinomial. It can be factored as $(x-3)^2 = 0$. Taking the square root of both sides gives $x-3 = 0$. Adding 3 to both sides, we get $x = 3$.