Question #N763
The function $f(x)$ is defined by $f(x) = \frac{x^2-1}{x+1}$. What is the value of $f(-2)$?
A. -3
B. -1
C. 1
D. 3
Correct Answer is: D
Substituting -2 for $x$ in the given function yields $f(-2) = \frac{(-2)^2 - 1}{-2 + 1}$. Simplifying the expression gives us $f(-2) = \frac{4-1}{-1} = \frac{3}{-1} = -3$.