Question #N787
If $x^2 + 2x - 15 = 0$, what are the solutions for $x$?
A. x = -5, x = 3
B. x = 5, x = -3
C. x = -15, x = 1
D. x = 15, x = -1
Correct Answer is: B
To solve for $x$, we can factor the quadratic equation: $(x + 5)(x - 3) = 0$. For this equation to equal 0, either $(x + 5) = 0$ or $(x - 3) = 0$. Solving for $x$ in each case, we get $x = -5$ or $x = 3$.