Question #N798
The function $f$ is defined by $f(x) = \sqrt{x^2 + 1}$. What is the value of $f(\sqrt{3})$?
A. 1
B. 2
C. $\sqrt{3}$
D. $\sqrt{10}$
Correct Answer is: B
Substituting $\sqrt{3}$ for $x$ in the function definition, we get $f(\sqrt{3}) = \sqrt{(\sqrt{3})^2 + 1}$. Simplifying, we have $f(\sqrt{3}) = \sqrt{3 + 1} = \sqrt{4} = 2$.