Question #N806
The function $f(x) = \frac{x^2 - 4}{x - 2}$ is defined for all real numbers except $x = 2$. What is the value of $f(4)$?
A. 2
B. 4
C. 6
D. 8
Correct Answer is: C
We can simplify the function by factoring the numerator: $f(x) = \frac{x^2 - 4}{x - 2} = \frac{(x+2)(x-2)}{x-2}$. Since $x \neq 2$, we can cancel the common factor of $x-2$ to get $f(x) = x + 2$. Therefore, $f(4) = 4 + 2 = 6$.