OpenSAT

The standard form of the equation of a circle is $(x-h)^2 + (y-k)^2 = r^2$, where $(h,k)$ is the center of the circle, and $r$ is the radius. In this case, the equation is already in standard form, and we can see that $r^2 = 25$. Therefore, the radius of the circle is $\sqrt{25} = 5$.