Question #N855
The expression is equivalent to $\frac{a}{b}$, where *a* and *b* are integers with no common factors. What is the value of *b*?
A. 4
B. 16
C. 64
D. 256
Correct Answer is: C
Simplify the given expression: \begin{align*} \frac{16x^2 + 64}{8x^2 + 32} &= \frac{16(x^2 + 4)}{8(x^2 + 4)}\\ &= \frac{16}{8} \\ &= 2. \end{align*} To express 2 as a fraction in the form $\frac{a}{b}$, where *a* and *b* have no common factors, we can rewrite it as $\frac{2}{1}$. Thus, the value of *b* is 1.