Question #N860
If $x^2 - 6x + 9 = 0$, what is the value of $x$?
A. 3
B. 6
C. 9
D. 18
Correct Answer is: A
The given equation is a perfect square trinomial, which can be factored as $(x-3)^2 = 0$. Taking the square root of both sides, we get $x - 3 = 0$. Adding 3 to both sides, we get $x = 3$.