OpenSAT

To solve for $x$, we can factor the quadratic equation. The factors of -15 that add up to -2 are -5 and 3. So, the equation factors as $(x - 5)(x + 3) = 0$. Setting each factor equal to zero, we get $x - 5 = 0$ or $x + 3 = 0$. Solving for x, we find $x = 5$ or $x = -3$. Since the problem asks for the value of x, and 5 is a choice, x = 5 is the correct answer.