Question #N956
If the function $f(x) = \frac{x^2 + 3x + 2}{x + 1}$ is defined for all real numbers except for $x = -1$, what is the value of $f(2)$?
A. 0
B. 1
C. 4
D. 8
Correct Answer is: C
To find f(2), we substitute $x = 2$ into the function: $f(2) = \frac{2^2 + 3(2) + 2}{2 + 1}$. Simplifying, we get $f(2) = \frac{4 + 6 + 2}{3} = \frac{12}{3} = 4$. Therefore, the value of f(2) is 4.