Question #N987
If $x$ is a real number, and $x^2 - 4x + 4 = 0$, what is the value of $x + 1$?
A. 1
B. 2
C. 3
D. 4
Correct Answer is: C
The equation $x^2 - 4x + 4 = 0$ factors as $(x-2)^2 = 0$. This tells us that $x - 2 = 0$, or $x = 2$. Therefore, $x + 1 = 2 + 1 = 3$.